Let $\alpha, \beta$ be the roots of $x^2+5 x+6=0$ and $\gamma, \delta$ be the roots of $y^2+6 y+7=0$. Then…

Let $\alpha, \beta$ be the roots of $x^2+5 x+6=0$ and $\gamma, \delta$ be the roots of $y^2+6 y+7=0$. Then the equation of the circle with $(\alpha, \gamma)$ and $(\beta, \delta)$ as the extremities of a diameter is
  1. $x^2+y^2+5 x+6 y+10=0$
  2. $x^2+y^2+5 x+6 y+11=0$
  3. $x^2+y^2+5 x+6 y+13=0$
  4. $x^2+y^2+5 x+6 y+12=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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