Let $\mathrm{A}$ be the region enclosed by the parabola $y^2=2 x$ and the line $x=24$. Then the maximum area of the rectangle inscribed in the region $\mathrm{A}$ is________

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Aicharya · Accepted Answer

$\begin{aligned} & A=2\left(24-\frac{b^2}{2}ight) \cdot b \ & \frac{d A}{d b}=0 \quad \Rightarrow \quad b=4 \ & A=2(24-8) 4 \ & =128\end{aligned}$

Let $\mathrm{A}$ be the region enclosed by the parabola $y^2=2 x$ and the line $x=24$. Then the maximum area…

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