Let $L L^{\prime}$ be the latus rectum through the focus $S$ of a hyperbola and $A^{\prime}$ be the opposite…

Let $L L^{\prime}$ be the latus rectum through the focus $S$ of a hyperbola and $A^{\prime}$ be the opposite vertex of the hyperbola. If triangle $A^{\prime} L L^{\prime}$ is equilateral, then the eccentricity of the hyperbola is
  1. $\frac{\sqrt{3}+1}{\sqrt{3}}$
  2. $\frac{\sqrt{3}+1}{\sqrt{2}}$
  3. $\frac{\sqrt{3}+1}{\sqrt{5}}$
  4. $\sqrt{3}+1$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

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