Let $P(r)=\frac{Q}{\pi R^4} r$ be the charge density distribution for a solid sphere of radius $R$ and total…
Let $P(r)=\frac{Q}{\pi R^4} r$ be the charge density distribution for a solid sphere of radius $R$ and total charge $Q$. for a point ' $p$ ' inside the sphere at distance $r_1$ from the centre of the sphere, the magnitude of electric field is
0
$\frac{Q}{4 \pi \varepsilon_0 r_1^2}$
$\frac{Q r_1^2}{4 \pi \varepsilon_0 R^4}$
$\frac{Q_1^2}{3 \pi \varepsilon_0 R^4}$
Solution
$
E 4 \pi r_1^2=\frac{\int_0^{r_1} \frac{Q}{\pi R^4} r 4 \pi r^2 d r}{\varepsilon_0} \Rightarrow E=\frac{Q r_1^2}{4 \pi \varepsilon_0 R^4} .
$
