Let θ be the angle between the vectors a → and b → , where a → = 4 , b → = 3…

Let θ be the angle between the vectors a and b, where a=4,b=3 and θπ4,π3. Then a-b×a+b2+4a·b2 is equal to ______

Solution

a-b×a+b2+4a·b2

=a×a+a×bb×ab×b2+4ab2

=4a×b2+a·b2=4a2b2=4×9×16=576

Asked in: JEE Main 2022 (25 Jun Shift 1)

Practice more Vectors questions on Aicharya