Let $f: R ightarrow R$ be defined by $f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \ x^2, & -1

Question

Let $f: R ightarrow R$ be defined by $f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \ x^2, & -1 < x < 1 \ 2-x, & x \geq 1\end{array}ight.$ Then the value of $f(-1.75)+f(0.5)+f(1.5)$ is

Aicharya · Accepted Answer

$\begin{aligned} & f(-1.75)+f(0.5)+f(1.5) \ &=(-1.75+2)+(0.25)+(2-1.5) \ &=0.25+0.25+0.5 \ &=1\end{aligned}$

Let $f: R \rightarrow R$ be defined by $f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \\ x^2, & -1 < x < 1 \\…

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