Let θ be an angle in the standard position such that the point ( - 5 , 12 ) lies on its terminal side,…

Let θ be an angle in the standard position such that the point (-5,12) lies on its terminal side, then
  1. |sinθ|=-sinθ
  2. |cosθ|=cosθ
  3. |tanθ|=-tanθ
  4. |cosecθ|=-cosecθ

Solution

Clearly, the point -5,12 lies in second quadrant. Since, it's x-coordinate is negative and y-coordinate is positive.

We know that, in second quadrant sinθ & cosecθ are positive and cosθ, secθ, tanθ & cotθ are negative.

So, by using definition of modulus function, we get |sinθ|=sinθ|cosθ|=-cosθ|tanθ|=-tanθ|cosecθ|=cosecθ.

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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