Let $A B C D E F$ be a regular hexagon with the vertices $A, B, C, D, E$ and $F$ counter clockwise. Then,…
- $B C+C D$
- $C D+D E$
- $A F+F E$
- $F E+E D$
Solution

$ \begin{aligned} \mathbf{A B}+\mathbf{B C} & =\mathbf{A C} \\ \text { and } \mathbf{F E}+\mathbf{E D} & =\mathbf{F D} \end{aligned} $ Since, $A B C D E F$ is regular hexagon. AC must be parallel to FD. $\therefore \mathbf{A B}+\mathbf{B C}$ is parallel to $\mathbf{F E}+\mathbf{E D}$
Asked in: AP EAMCET 2021 (23 Aug Shift 1)