Let $S$ be a non-empty subset of R. Consider the following statement: $\mathrm{P}$ : There is a rational…
Let $S$ be a non-empty subset of R. Consider the following statement:
$\mathrm{P}$ : There is a rational number $\mathrm{x} \in \mathrm{S}$ such that $\mathrm{x}>0$.
Which of the following statements is the negation of the statement $P$ ?
There is no rational number $x \in S$ such that $x \leq 0$
Every rational number $x \in S$ satisfies $x \leq 0$
$x \in S$ and $x \leq 0 \Rightarrow x$ is not rational
There is a rational number $x \in S$ such that $x \leq 0$
Solution
$P$ : there is a rational number $x \in S$ such that $x>0$
$\sim P$ : Every rational number $\mathrm{x} \in \mathrm{S}$ satisfies $\mathrm{x} \leq 0$