Let $A$ be a $2 \times 2$ matrix with real entries. Let $I$ be the $2 \times 2$ identity matrix.…

Let $A$ be a $2 \times 2$ matrix with real entries. Let $I$ be the $2 \times 2$ identity matrix. $\operatorname{Tr}(A)$ denotes the sum of diagonal entries of $A$. Assume that $A^2=I$ Statement I If $A \neq I$ and $A \neq-1$, then $\operatorname{det} A=-1$ Statement II If $A \neq I$ and $A \neq-1$, then $\operatorname{Tr} A \neq 0$
  1. Statement I is true, statement II is true, statement II is a correct explanation for statement I
  2. Statement I is true, statement II is true, statement II is not a correct explanation for statement I
  3. Statement I is true, statement II is false
  4. Statement I is false, statement II is true

Solution

Let $A=\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]$ $A^2=\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]=I$ Here, $A^2=I,|A|=-1$ and $A \neq \pm I$ $\operatorname{Tr}(A)=0$ $\therefore$ Statement I is true. Statement II is false.

Asked in: AP EAMCET 2021 (24 Aug Shift 2)

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