Let $f$ be a function such that $f(x)+3 f\left(\frac{24}{x}\right)$ $=4 x, x \neq 0$. Then $f(3)+f(8)$ is…
- $11$
- $10$
- $12$
- $13$
Solution
Put $x=3 \quad f(3)+3 f(8)=12$
Put $x=8 \quad f(8)+3 f(3)=32$
Add both $\quad 4(\mathrm{f}(3)+\mathrm{f}(8))=44$
$f(3)+f(8)=11$
Asked in: JEE Main 2025 (03 Apr Shift 2)