Let $P_1, P_2, \ldots ., P_{15}$ be 15 points on a circle. The number of distinct triangles formed by points…

Let $P_1, P_2, \ldots ., P_{15}$ be 15 points on a circle. The number of distinct triangles formed by points $P_i, P_j, P_k$ such that $i+j+k \neq 15$ is
  1. $449$
  2. $419$
  3. $455$
  4. $443$

Solution


Total number of distinct triangles $={ }^{15} C_3$ Now, we have to exclude that cases in which $i+j+k=15$
Total number of cases in which $i+j+k=15$ is 12 . $\therefore$ Total number of required triangles $={ }^{15} C_3-12=455-12=443$

Asked in: AP EAMCET 2022 (07 Jul Shift 1)

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