Let $|z_{1}-8-2i| \leq 1$ and $|z_{2}-2+6i| \leq 2$, $z_{1}, z_{2} \in \mathbb{C}$. Then the minimum value of $|z_{1}-z_{2}|$ is:

Question

Aicharya · Accepted Answer

$\begin{aligned} & \because \mathrm{AB}=\sqrt{100}=10 \ & 	herefore\left|\mathrm{Z}_1-\mathrm{Z}_2ight|_{\min }=10-2-1=7\end{aligned}$

Let $|z_{1}-8-2i| \leq 1$ and $|z_{2}-2+6i| \leq 2$, $z_{1}, z_{2} \in \mathbb{C}$. Then the minimum value…