Let $\bar{a}=4 \bar{i}+5 \bar{j}-\bar{k}, \bar{b}=\bar{i}-4 \bar{j}+5 \bar{k}, \bar{c}=3…

Let $\bar{a}=4 \bar{i}+5 \bar{j}-\bar{k}, \bar{b}=\bar{i}-4 \bar{j}+5 \bar{k}, \bar{c}=3 \bar{i}+\bar{j}-\bar{k}$ and let $\bar{\alpha}$ be a vector perpendicular to both $\bar{a}$ and $\bar{b}$ such that $\bar{\alpha} \cdot \bar{c}=63$. Then $\bar{\alpha}=$
  1. $7 \bar{i}-7 \bar{j}-7 \bar{k}$
  2. $3 \bar{i}-3 \bar{j}-3 \bar{k}$
  3. $21 \bar{i}-21 \bar{j}-21 \bar{k}$
  4. $21 \bar{i}-7 \bar{j}-7 \bar{k}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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