Let $A D$ and $B C$ be two vertical poles at $A$ and $B$ respectively on a horizontal ground. If $A D=8…
- 8
- 5
- 4
- 7
Solution
$\begin{aligned} & f(x)=M D^2+M C^2 \\ & \Rightarrow f(x)=x^2+8^2+(10-x)^2+11^2 \\ & \Rightarrow f^{\prime}(x)=2 x-2(10-x) \\ & \Rightarrow f^{\prime}(x)=4 x-20 \\ & \text { for } f(x) \text { to be minimum } x=5\end{aligned}$Asked in: MHT CET 2022 (08 Aug Shift 2)
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