Let $m$ and $n$ be two integers such that $0 \leq m \leq 10$ and $0 \leq n \leq 10$. Then, the number of…

Let $m$ and $n$ be two integers such that $0 \leq m \leq 10$ and $0 \leq n \leq 10$. Then, the number of ordered pairs $(m, n)$ such that $x^2+m x+n=0$ has real roots is
  1. 71
  2. 73
  3. 75
  4. 72

Solution

Given, $x^2+m x+n=0$ has real roots. $ \begin{array}{ll} \therefore m^2-4 n \geq 0 \quad 0 \leq m, n \leq 10, \quad m^2 \geq 4 n \\ m=10, & n=\{0,1,2, \ldots, 10\}=11 \\ m=9, & n=\{0,1,2, \ldots, 10\}=11 \\ m=8, & n=\{0,1,2, \ldots, 10\}=11 \\ m=7, & n=\{0,1,2, \ldots, 10\}=11 \\ m=6, & n=\{0,1,2, \ldots, 9\}=10 \\ m=5, & n=\{0,1,2, \ldots, 6\}=7 \\ m=4, & n=\{0,1,2,3,4\}=5 \\ m=3, & n=\{0,1,2\}=3 \\ m=2, & n=\{0,1\}=2 \\ m=1, & n=\{0\}=1 \\ m=0, & n=\{0\}=1 \end{array} $ $\therefore \quad$ Number of order pair of $(m, n)$ is $ 11+11+11+11+10+7+5+3+2+1+1=73 $

Asked in: AP EAMCET 2021 (25 Aug Shift 1)

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