Let $A$ and $B$ be two independent events such that $P(B)>P(A)$. If the probability that both A and B happen…

Let $A$ and $B$ be two independent events such that $P(B)>P(A)$. If the probability that both A and B happen is $\frac{1}{12}$ and the probability that neither Anor B happens is $\frac{1}{2}$ then
  1. $P(A)=\frac{1}{6}, P(B)=\frac{1}{2}$
  2. $\mathrm{P}(\mathrm{A})=\frac{1}{4}, \mathrm{P}(\mathrm{B})=\frac{1}{3}$
  3. $\mathrm{P}(\mathrm{A})=\frac{1}{6}, \mathrm{P}(\mathrm{B})=\frac{1}{5}$
  4. $\mathrm{P}(\mathrm{A})=\frac{1}{6}, \mathrm{P}(\mathrm{B})=\frac{1}{3}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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