Let $A$ and $B$ be two events with $P(A)=\frac{1}{7}$, $P\left(\frac{A}{B}\right)=\frac{2}{3}$ and $P(B)=\frac{2}{7}$. Then, the value $P\left(\frac{B}{A}\right)$ is

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Aicharya · Accepted Answer

$\begin{aligned} P(B / A) & =\frac{P(A / B) P(B)}{P(A)} \ & =\frac{(2 / 5)(2 / 7)}{(1 / 7)}=\frac{4}{5}\end{aligned}$

Let $A$ and $B$ be two events with $P(A)=\frac{1}{7}$, $P\left(\frac{A}{B}\right)=\frac{2}{3}$ and…

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