Let $P=(-1,0), Q=(0,0)$ and $R=(3,3 \sqrt{3})$ be three points. Then the equation of the bisector of the…

Let $P=(-1,0), Q=(0,0)$ and $R=(3,3 \sqrt{3})$ be three points. Then the equation of the bisector of the $\angle \mathrm{PQR}$ is
  1. $\sqrt{3 x}+y=0$
  2. $x+\frac{\sqrt{3}}{2} y=0$
  3. $\frac{-\sqrt{3}}{2} x+y=0$
  4. $x+\sqrt{3} y=0$

Solution

Given $\mathrm{P}(-1,0), \mathrm{B}=(0,0), R=(3,3 \sqrt{3})$
Now slope of line $Q M=\tan \frac{2 \pi}{3}=-\sqrt{3}$ $\therefore$ Equation of line $Q M=y-\sqrt{3} x=0 \Rightarrow \sqrt{3} x+y=0$

Asked in: AP EAMCET 2023 (15 May Shift 2)

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