Let $\alpha, \beta, \gamma$ and $\delta$ be the coefficients of $x^7, x^5, x^3$ and $x$ respectively in the…

Let $\alpha, \beta, \gamma$ and $\delta$ be the coefficients of $x^7, x^5, x^3$ and $x$ respectively in the expansion of $\left(x+\sqrt{x^3-1}\right)^5+\left(x-\sqrt{x^3-1}\right)^5, x\gt1$. If u and v satisfy the equations $\begin{aligned} & \alpha u+\beta v=18 \\ & \gamma u+\delta v=20 \end{aligned}$ then $u+v$ equals :
  1. 5
  2. 3
  3. 4
  4. 8

Solution

$\begin{aligned} & \left(x+\sqrt{x^3-1}\right)^5+\left(x-\sqrt{x^3-1}\right)^5 \\ & -\left[{ }^5 C_0 x^5+{ }^5 C_1 x^4\left(\sqrt{x^3-1}\right)+\ldots \ldots+{ }^5 C_5\left(\sqrt{x^3-1}\right)^5\right]+ \\ & {\left[{ }^5 C_0 x^5-{ }^5 C_1 x^4\left(\sqrt{x^3-1}\right)+\ldots \ldots .+{ }^{-5} C_5\left(\sqrt{x^3-1}\right)^5\right]} \\ & =2\left[x^5+{ }^5 C_2 x^3\left(x^3-1\right)+{ }^5 C_4\left(x^3-1\right)^2\right] \\ & =10 x^7+20 x^6+2 x^5-20 x^4-20 x^3+10 x \end{aligned}$ Now $\alpha=10, \beta=2, \gamma=-20, \delta=10$ Also, $\begin{aligned} & \left.\begin{array}{c} 10 u+2 v=18 \\ -20 u+10 v=20 \end{array}\right\} u=1, v=4 \\ & u+v=5 \end{aligned}$

Asked in: JEE Main 2025 (22 Jan Shift 2)

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