Let a n be the n t h term of a G.P. of positive terms. If ∑ n = 1 100 a 2 n + 1 = 200 and ∑ n =…

Let an be the nth term of a G.P. of positive terms. If n=1100a2n+1=200 and n=1100a2n=100, then n=1200an is equal to:
  1. 300
  2. 225
  3. 175
  4. 150

Solution

Let GP is a,ar,ar2

n=1100a2n+1=a3+a5+a201=200ar2(r200-1)r2-1=200   1

n=1100a2n=a2+a4+a200=100=arr200-1r2-1=100     2

Form 1 and 2r=2

adding both,

a2+a3+a200+a201=300ra1+a200=300

n=1200300r=150

Asked in: JEE Main 2020 (09 Jan Shift 2)

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