Let a → = i ^ + 2 j ^ - k ^ ,   b → = i ^ - j ^ and c → = i ^ - j ^ - k ^ be three…

Let a=i^+2j^-k^, b=i^-j^ and c=i^-j^-k^ be three given vectors. If r is a vector such that r×a=c×a and r·b=0, then r·a is equal to

Solution

r-c×a=0

 r=c+λa

taking dot product with b

Now, 0=b·c+λa·b

 λ=-b·ca·b=-2-1=2

So, r·a=a·c+2a2=0+2×6=12

Asked in: JEE Main 2021 (25 Feb Shift 1)

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