Let a , b and c be the lengths of the sides of a triangle with its opposite angles A , B and C respectively.…

Let a,b and c be the lengths of the sides of a triangle with its opposite angles A,B and C respectively. If a=3, b=4 and A=sin-134, then the angle B is
  1. 30°
  2. 45°
  3. 90°
  4. 60°

Solution

Given, a=3b=4

and A=sin-1(34)⇒sinA=34

Using sine rule, we get

aSinA= bsinB

⇒ sinB=bsinAa

⇒sinB=4×343

⇒sin B=1

⇒B= sin-1 (1)

⇒B=90°.

Asked in: MHT CET Full Test 9

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