Let a → = − 5 i ^ + j ^ − 3 k ^ , b → = i ^ + 2 j ^ − 4 k ^ and c → = a → × b → × i ^ × i ^ × i ^ . Then c →…

Let a=5i^+j^3k^, b=i^+2j^4k^ and c=a×b×i^×i^×i^. Then ci^+j^+k^ is equal to
  1. -12
  2. -10
  3. -13
  4. -15

Solution

Given: 

a=5i^+j3k^ and b=i^+2j^4k^

a×b×i^=ai^bbi^a

a×b×i^=5ba

a×b×i^=5ba×i^×i^

a×b×i^=11j^+23k^×i^×i^

a×b×i^=11k^+23j^×i^

a×b×i^=11j^23k^

c.i^+j^+k^=1123

c.i^+j^+k^=12

Asked in: JEE Main 2024 (01 Feb Shift 1)

Practice more Vectors questions on Aicharya