Let a → = 2 i ^ + 7 j ^ - k ^ ,   b ^ = 3 i ^ + 5 k ^ and c → = i ^ - j ^ + 2 k ^ Let d…

Let a=2i^+7j^-k^, b^=3i^+5k^ and c=i^-j^+2k^  Let d be a vector which is perpendicular to both a and b, and c·d=12. Then-i^+j^-k^·c×d  is equal to
  1. 24
  2. 44
  3. 42
  4. 48

Solution

Given,

a=2i^+7j^-k^, b^=3i^+5k^ and c=i^-j^+2k^ 

And  d be a vector which is perpendicular to both a and b,

So, d=λa×b

Now finding, a×b=i^j^k^27-1305

a×b=35i^-13j^-21k^

So, d=λ35i^-13j^-21k^

Also given, 

c·d=12

c·d=i^-j^+2k^·λ35i^-13j^-21k^

λ(35+13-42)=12

 λ = 2

So, c×d=2×i^j^k^1-1235-13-21

c×d=247i^+91j^+22k^

Now finding,

-i^+j^-k^·c×d=2-i^+j^-k^47i^+91j^+22k^

-i^+j^-k^·c×d=2-47+91-22=44

Asked in: JEE Main 2023 (10 Apr Shift 2)

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