Let a → = 2 i ^ - 3 j ^ + 4 k ^ and b → = 7 i ^ + j ^ - 6 k ^ If r → × a → = r…

Let a=2i^-3j^+4k^ and b=7i^+j^-6k^ If r×a=r×b,r·(i^+2j^+k^)=-3, then r·(2i^-3j^+k^) is equal to:
  1. 12
  2. 8
  3. 13
  4. 10

Solution

r×a-r×b=0

r×a-b=0

r=λa-b

r=λ-5i^-4j^+10k^

Also r·i^+2j^+k^=-3

λ-5-8+10=-3

λ=1

Now r=-5i^-4j^+10k^

=r·2i^-3j^+k^

=-10+12+10=12

Asked in: JEE Main 2021 (17 Mar Shift 1)

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