Let A 1 = x , y : x ≤ y 2 , x + 2 y ≤ 8 and A 2 = x , y : x + y ≤ k . If 27 (Area A 1 ) =…

Let A1=x,y:xy2,x+2y8 and A2=x,y:x+yk. If 27 (Area A1=5(Area A2), then k is equal to

Solution

A1=x,y:xy2,x+2y8 and

A2=x,y:x+yk

Area A1=202y2dy+248-2ydy

=2y3302+8y-y224

Area A1=2×203=403

Area A2=4×12k2

Area A2=2k2

Given 27Area A1=5Area A2

27×403=5×2k2

k=6

Asked in: JEE Main 2022 (27 Jun Shift 1)

Practice more Area Under Curves questions on Aicharya