Let A = [ x + 1 ] [ x + 2 ]     [ x + 3 ] [ x ]   [ x + 3 ]     [ x + 3 ] [ x ] [ x…

Let A=[x+1][x+2]  [x+3][x] [x+3]  [x+3][x][x+2] [x+4], where [x] denotes the greatest integer less than or equal to x. If det(A)=192, then the set of values of x is in the interval:
  1. [62,63)
  2. [65,66)
  3. [60,61)
  4. [68,69)

Solution

Given, A=[x+1][x+2][x+3][x][x+3][x+3][x][x+2][x+4]

A=[x]+1[x]+2[x]+3[x][x]+3[x]+3[x][x]+2[x]+4

R1R1R3,R2R2R3

A=101011[x][x]+2[x]+4

det(A)=1([x]+4+[x]+2)1([x])

=3[x]+6

Given, det(A)=192

192=3[x]+6

3[x]=186

[x]=62

x[62,63)

Asked in: JEE Main 2021 (27 Aug Shift 2)

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