Let a ,   b ,   c be three non-zero real numbers such that the equation 3 a cos ⁡ x + 2 b…

Let a, b, c be three non-zero real numbers such that the equation 3acosx+2bsinx=c, x-π2, π2 has two distinct real roots α and β with α+β=π3. Then, the value of ba is

Solution

3cosx+2basinx=ca
Now, 3cosα+2basinα=ca i   
3cosβ+2basinβ=ca ii 

From equations i and ii

3cosα-cosβ+2basinα-sinβ=0
3-2sinα+β2sinα-β2+2ba2cosα+β2sinα-β2=0

-3+23·ba=0
ba=12=0.5

Asked in: JEE Advanced 2018 (Paper 1)

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