Let a ,   b and   c be the 7 t h ,   11 t h and 13 t h terms respectively of a non-constant A…

Let a, b and  c be the 7th, 11th and 13th terms respectively of a non-constant A.P. . If these are also the three consecutive terms of a G.P. , then ac is equal to:
  1. 2
  2. 713
  3. 12
  4. 4

Solution

Let the first terms of A.P. be A and common difference be d, then

a=A+6d

b=A+10d

c=A+12d

Given a, b, c are in G. P. b2=ac

A+10d2=A+6dA+12d

A2+100d2+20Ad=A2+18Ad+72d2

A=-14d

Now ac=A+6dA+12d=-14d+6d-14d+12d=-8d-2d=4

Asked in: JEE Main 2019 (09 Jan Shift 2)

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