Let γ 1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant…

Let γ1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio γ1γ2 is:
  1. 2735
  2. 3527
  3. 2521
  4. 2125

Solution

As we know, Cv=fR2

and Cp=Cv+R=fR2+R

Therefore, γ=CpCv=1+2f

For monatomic gas, f=3 and hence γ1=53

For diatomic gas, f=5 and hence γ2=75

Required ratio, γ1γ2=2521

Asked in: JEE Main 2023 (24 Jan Shift 2)

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