Let α > 0 , be the smallest number such that the expansion of x 2 3 + 2 x 3 30 has a term β x…

Let α>0, be the smallest number such that the expansion of x23+2x330 has a term βx-α,βN. Then α is equal to _____ .

Solution

General term of the binomial expansion of x23+2x330 is

Tr+1=Cr30x2/330-r2x3r

Tr+1=Cr30·2r·x60-11r3

So, for term of the form βx-α, we have

60-11r3<0

11r>60

r>6011r=6

So,

T7=C630·26x-2

We have also observed β=C63026 is a natural number.

α=2

Asked in: JEE Main 2023 (31 Jan Shift 1)

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