Paragraph: A fair die is tossed repeatedly until a six is obtained. Let $X$ denotes the number of tosses…

Paragraph: A fair die is tossed repeatedly until a six is obtained. Let $X$ denotes the number of tosses required. Question: The conditional probability that $X \geq 6$ given $X>3$ equals
  1. $\frac{125}{216}$
  2. $\frac{25}{216}$
  3. $\frac{5}{36}$
  4. $\frac{25}{36}$

Solution

$P((X \geq 6) /(X>3))$ $ \begin{aligned} & =\frac{P((X>3) /(X \geq 6)) \cdot P(X \geq 6)}{P(X>3)} \\ & =\frac{1 \cdot\left[\left(\frac{5}{6}\right)^5 \cdot \frac{1}{6}+\left(\frac{5}{6}\right)^6 \cdot \frac{1}{6}+\ldots \infty\right]}{\left[\left(\frac{5}{6}\right)^3 \cdot \frac{1}{6}+\left(\frac{5}{6}\right)^4 \cdot \frac{1}{6}+\ldots \infty\right]}=\frac{25}{36} \\ & \end{aligned} $

Asked in: JEE Advanced 2009 (Paper 1)

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