Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
${}_{1}^{2}X + {}_{1}^{2}X = {}_{2}^{4}Y$
The binding energies per nucleon ${}_{1}^{2}X$ and ${}_{2}^{4}Y$ are $1.1 MeV$ and $7.6 MeV$ respectively. The energy released in this process is_____ $MeV$ .

Question

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:

${}_{1}^{2}X + {}_{1}^{2}X = {}_{2}^{4}Y$

The binding energies per nucleon ${}_{1}^{2}X$ and ${}_{2}^{4}Y$ are $1.1 MeV$ and $7.6 MeV$ respectively. The energy released in this process is_____ $MeV$ .

Aicharya · Accepted Answer

Energy released in the given process = Binding energy of product - Binding energy of reactants. = 7 . 6 &#215; 4 - 1 . 1 &#215; 2 &#215; 2 = 30 . 4 - 4 . 4 = 26 MeV

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: X 1 2 + X 1…

Solution