The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of $15 Ω$ resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of $10 V$ is maintained across AC.

Question

Aicharya · Accepted Answer

x - 10 100 + x - y 15 + x - 0 10 = 0 53 x - 20 y = 30 &#160; &#160; &#8230; &#8230; ( 1 ) y - 10 60 + y - x 15 + y - 0 5 = 0 17 y - 4 x = 10 &#160; &#160; &#8230; &#8230; ( 2 ) on solving ( 1 ) &#160; &#38; &#160; ( 2 ) x = 0 . 865 y = 0 . 792 &#916; V = 0 . 073 R = 15 &#160; &#937; &#8658; i = 4 . 87 &#160; mA

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 Ω…

Solution

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 &#937;…

Solution

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 Ω…