The formula of the purple colour formed in Laissaigne's test for sulphur using sodium nitroprusside is

1. ${\mathrm{Na}}_4\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_5\left(\mathrm{NOS}\right)\right]$
2. $\mathrm{NaFe}\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]$
3. $\mathrm{Na}\left[\mathrm{Cr}{\left({\mathrm{NH}}_3\right)}_2{\left(\mathrm{NCS}\right)}_4\right]$
4. ${\mathrm{Na}}_2\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_5\left(\mathrm{NO}\right)\right]$

Solution

Asked in: JEE Main 2022 (28 Jun Shift 1)

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