Product A and B formed in the following set of reactions are:

The reaction is known as hydroboration-oxidation. In this reaction, ${\mathrm{B}}_2{\mathrm{H}}_6$ adds to the double bond of propene, resulting in the formation of an organoborane intermediate. Subsequent treatment with ${\mathrm{H}}_2{\mathrm{O}}_2$ converts the organoborane intermediate to an alcohol. Hydration follows anti-Markownikoff's rule.

In this hydration reaction, 1-methylcyclohexene (an alkene) is reacted with aqueous ${\mathrm{H}}_3{\mathrm{O}}^{+}$ (formed from water and a strong acid such as ${\mathrm{H}}_2{\mathrm{SO}}_4$), resulting in Markovnikov addition of water across the pi bond. The product is an alcohol.