Match the thermodynamics processes taking place in a system with the correct conditions. In the table :…

Match the thermodynamics processes taking place in a system with the correct conditions. In the table : Q is the heat supplied, W is the work done and U is change in internal energy of the system.

  Process   Condition
(I) Adiabatic (A) W=0
(II) Isothermal (B) Q=0
(III) Isochoric (C) U0,W0,Q0
(IV)

Isobaric

(D) U=0
  1. (I) - (A), (II) - (B), (III) - (D), (IV) - (D)
  2. (I) - (B), (II) - (A), (III) - (D), (IV) - (C)
  3. (I) - (A), (II) - (A), (III) - (B), (IV) - (C)
  4. (I) - (B), (II) - (D), (III) - (A), (IV) - (C)

Solution

In Adiabatic ΔQ=0,i.e., Exchange of heat does not take place.

In Isothermal ΔU=0,i.e., Temperature does not change therefore internal energy also remains constant.

In Isochoric ΔW=0,i.e., Volume remains constant therefore work done is zero.

In Isobaric U0, W0, Q0
W=P.V, Volume changes so work done is not equal to zero.
U=f2PV, Volume changes therefore internal energy changes.
 Q=nCpT, Temperature changes therefore heat also changes.

 

 

Asked in: JEE Main 2020 (04 Sep Shift 2)

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