Match List - I with List - II. List-I List-II (a) Fe ( CN ) 6 3 - (i) 5 . 92 BM (b) Fe H 2 O 6 3 + (ii) 0 BM…

Match List - I with List - II.

List-I List-II
(a) Fe(CN)63- (i) 5.92 BM
(b) FeH2O63+ (ii) 0 BM
(c) [Fe(CN)6]4- (iii) 4.90 BM
(d) FeH2O62+ (iv) 1.73 BM

Choose the correct answer from the options given below.

  1. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
  2. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
  3. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
  4. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Solution

Fe(CN)63- has Fe3+ central ion d5

Electronic configuration (SFL)

t2geg2,2,10,0

n=1

Magnetic moment:

μ=nn+2 BM

=1(1+2)

=3

=1.73 BM

FeH2O63+: has d5 electrons.

Electronic configuration (WFL)

t2ge1,1,1g1,1

n=5

μ=5(5+2)=35

=5.92 B.M.

Fe(CN)64- has d6 electrons.
Electronic configuration (SFL)

t2g2,2,1eg0,0

n=0

μ=0 B.M.

FeH2O62+ has d6 electron
Electronic configuration: (WFL)

t2g2,2,1eg1,1

n=4

μ=4(4+2)=4.90 B.M.

Asked in: NEET 2021

Practice more Coordination Compounds questions on Aicharya