Match List - I with List - II. List-I (Reactants) List-II Products (A) Phenol, Zn / ∆ (I) Salicylaldehyde…

Match List - I with List - II.

List-I (Reactants) List-II Products
(A) Phenol, Zn/∆ (I) Salicylaldehyde
(B) Phenol, CHCl3,NaOH,HCl (II) Salicylic acid
(C) Phenol, CO2,NaOH,HCl (III) Benzene
(D) Phenol,  Conc. HNO3 (IV) Picric acid

Choose the correct answer from the options given below.

  1. (A)-(IV), (B)-(II), (C)-(I), (D)-(III) 
  2. (A)-(IV), (B)-(I), (C)-(II), (D)-(III) 
  3. (A)-(III), (B)-(I), (C)-(II), (D)-(IV) 
  4.  (A)-(III), (B)-(IV), (C)-(I), (D)-(II) 

Solution

(A) When phenol is distilled with Zn-dust, it gives benzene. it is an example of reduction. Phenol loses one O atom.

(B) When phenol is treated with CHCl3 and NaOH followed by acidification, salicyaldehyde is formed. The reaction is known as Reimer Tiemann reaction.

(C) Reaction of phenol with sodium hydroxide and carbon dioxide is Kolbe's Schmidt reaction that is a electrophilic substitution reaction resulting in the formation of salicylic acid as shown in the reaction.

The major product obtained on interaction of phenol with sodium hydroxide and carbon dioxide is salicylic acid.

(D) With concentrated nitric acid, phenol is converted to 2, 4, 6-Trinitrophenol. The product is commonly known as picric acid.

Asked in: JEE Main 2024 (01 Feb Shift 2)

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