Match List I with List II Choose the correct answer from the options given below:

Match List I with List II

Choose the correct answer from the options given below:

  1. A-I, B-II, C-III, D-IV
  2. A-IV, B-I, C-II, D-III
  3. A-III, B-IV, C-I, D-II
  4. A-II, B-I, C-IV, D-III

Solution

pKa=-logKa, here Ka acid dissociation constant. More the Ka value, stronger is the acidic nature of the respective acid.

Hence, the lower pKa value denotes a more powerful acid.  Phenols are more acidic than alcohols. Hence, ethanol has more pKa value. Nitro group is the electron withdrawing group, hence it increases the acidic nature of phenols.  Among the given phenols para nitrophenol  is stronger acid. The pKa values are matched below.

Ethanol 15.9

Phenol10

m-Nitrophenol 8.3

p-Nitrophenol7.1

Hence, the answer is option D.

Asked in: JEE Main 2024 (29 Jan Shift 2)

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