Match Lis-I with List-II. List-1 List-II A. Weak intermolecular forces of attraction I. Hexamethylenediamine…

Match Lis-I with List-II.

  List-1   List-II
A. Weak intermolecular forces of attraction I. Hexamethylenediamine
+ adipic acid
B. Hydrogen bonding II. AlEt3+TiCl4
C. Heavily branched polymer III. 2-chloro-1, 3-butadiene
D. High density polymer IV. Phenol + formaldehyde

Choose the correct answer from the options given below

  1. A-IV, B-II, C-III, D-I
  2. A-IV, B-I, C-III, D-II
  3. A-II, B-IV, C-I, D-III
  4. A-III, B-I, C-IV, D-II

Solution

(A) Weak Intermolecular Forces are present in polymer of 2-chloro, 1, 3-butadiene.It is a monomer of neoprene which is a rubber(elastomer.).
(B). Hydrogen Bonding is present in NYLON-6,6 which is a polymer of Hexamethylenediamine and adipic acid. This hydrogen bonding is due to the presence of amide group. 
(C) Heavily branched polymer is Bakelite which is polymer of phenol and formaldehyde. It is a crosslinked polymer.
(D) High density polymer(polyethylene) preparation requires Al(Et)3 and TiCl4 as a catalyst (Ziegler Natta Catalyst)

Asked in: JEE Main 2023 (13 Apr Shift 2)

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