In the adjoining figure, AB || CD and AB || EF. The value of x is:

In the adjoining figure, AB || CD and AB || EF. The value of x is:

  1. 40º

  2. 60º

  3. 70º

  4. 50º

Solution

$ \angle \text{FEC} + \angle \text{ECD} = 180^\circ $ $ \angle \text{ECD} = 180^\circ - 150^\circ = 30^\circ $ $ \angle x = \angle \text{BCE} = \angle \text{ECD} $ $ \angle x = 30^\circ + 30^\circ = 60^\circ $

Asked in: School

Practice more LINES AND ANGLES questions on Aicharya