A capacitor of capacitance C = 1   μ F is suddenly connected to a battery of 100   V through…

A capacitor of capacitance C=1 μF is suddenly connected to a battery of 100 V through a resistance R=100 Ω. The time taken for the capacitor to be charged to get 50 V is:

(Take ln2=0.69)

  1. 1.44×10-4 s
  2. 3.33×10-4 s
  3. 0.69×10-4 s
  4. 0.30×10-4 s

Solution

V=V01-e-tRC
50=1001-e-tRC
t=0.69×10-4 sec.

Asked in: JEE Main 2021 (27 Jul Shift 1)

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