In the above reactions, product A and product B respectively are:

One very common reaction of amide is Hoffmann's bromamide reaction in which amide get converted into amine having one carbon less than amide. For this reaction reagent is $({\mathrm{Br}}_2/\mathrm{KOH} \mathrm{or} \mathrm{KOBr})$.

Lithium aluminium hydride is very strong reducing agent which will convert amide into amine. Number of carbon is same in both amide and amine.