Arrange the following conformational isomers of n-butane in order of their increasing potential energy:

1. $\mathrm{I}<\mathrm{III}<\mathrm{IV}<\mathrm{II}$
2. $\mathrm{I}<\mathrm{IV}<\mathrm{III}<\mathrm{II}$
3. $\mathrm{II}<\mathrm{IV}<\mathrm{III}<\mathrm{I}$
4. $\mathrm{II}<\mathrm{III}<\mathrm{IV}<\mathrm{I}$

Solution

The order Potential energy of above conformations is Fully eclipsed $>$ Partial eclipsed $>$ Gauche $>$ Anti

Asked in: JEE Main 2021 (31 Aug Shift 2)

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