In the above compound, the bond orders of bonds I and II are:

1. $\left(\mathrm{I}\right)<2, \left(\mathrm{II}\right)>2$
2. $\left(\mathrm{I}\right)>2, \left(\mathrm{II}\right)>2$
3. $\left(\mathrm{I}\right)>2, \left(\mathrm{II}\right)<2$
4. $\left(\mathrm{I}\right)<2, \left(\mathrm{II}\right)<2$

Solution

Azide ion $\left({\mathrm{N}}_3^{-}\right)$    


Bond order: $\left(\mathrm{I}\right)<2$ 

Bond Order: $\left(\mathrm{II}\right)>2$

Due to the delocalisation in $\mathrm{I}$ double character increase in single bond and $\mathrm{II}$ triple bond character decrease in triple bond (double bond character comes).
 

Asked in: JEE Main 2018 (15 Apr)

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