An electron revolves around an infinite cylindrical wire having uniform linear charge density $2 \times 10^{- 8}$ $C m^{- 1}$ in circular path under the influence of attractive electrostatic field as shown in the figure. The velocity of electron with which it is revolving is ______________ $\times 10^{6} m s^{- 1}$ . Given mass of electron $= 9 \times 10^{- 31} kg$

Question

Aicharya · Accepted Answer

The electric field is given by E = 2 k &#955; r The required centripetal force is F = m v 2 r The force due to the field is equal to the required centripetal force, &#8658; 2 k &#955; r e = m v 2 r &#8658; v = 2 k &#955; e m = 2 &#215; 9 &#215; 10 9 &#215; 2 &#215; 10 - 8 &#215; 1 . 6 &#215; 10 - 19 9 &#215; 10 - 31 = 1 . 6 &#215; 4 &#215; 10 13 = 4 &#215; 2 &#215; 10 6 &#160; m &#160; s - 1 = &#160; 8 &#160; &#215; &#160; 10 6 &#160; m &#160; s - 1

An electron revolves around an infinite cylindrical wire having uniform linear charge density 2 × 10 -…

Solution

An electron revolves around an infinite cylindrical wire having uniform linear charge density 2 &#215; 10 -…

Solution

An electron revolves around an infinite cylindrical wire having uniform linear charge density 2 × 10 -…