A random variable $X$ has the distribution $\begin{array}{|c|c|c|c|} \hline X & 2 & 3 & 4 \ \hline P(X) & 0.3 & 0.4 & 0.3 \ \hline \end{array} $ Then, variance of the distribution is

Question

Aicharya · Accepted Answer

We have, X 2 3 4 P X 0 . 3 0 . 4 0 . 3 Mean, E X = 2 &#215; 0 . 3 + 3 &#215; 0 . 4 + 4 &#215; 0 . 3 = 3 Variance, &#963; 2 &#8658; &#160; &#963; 2 = 4 &#215; 0 . 3 + 9 &#215; 0 . 4 + 16 &#215; 0 . 3 - E X 2 &#8658; &#160; &#963; 2 = 9 . 6 - 9 = 0 . 6

$X$	$2$	$3$	$4$
$P (X)$	$0.3$	$0.4$	$0.3$

A random variable $X$ has the distribution $\begin{array}{|c|c|c|c|} \hline X & 2 & 3 & 4 \\ \hline P(X) & 0…

Solution