A block is simply released from the top of an inclined plane as shown in the figure above. The maximum…

A block is simply released from the top of an inclined plane as shown in the figure above. The maximum compression in the spring when the block hits the spring is :
  1. $\sqrt{6} \mathrm{~m}$
  2. $\sqrt{5} \mathrm{~m}$
  3. $1 \mathrm{~m}$
  4. $2 \mathrm{~m}$

Solution

$\begin{aligned} & \mathrm{w}_{\mathrm{g}}+\mathrm{w}_{\mathrm{Fr}}+\mathrm{w}_{\mathrm{s}}=\Delta \mathrm{KE} \\ & 5 \times 10 \times 5-0.5 \times 5 \times 10 \times \mathrm{x}-\frac{1}{2} \mathrm{Kx}^2=0-0 \\ & 250=25 \mathrm{x}+50 \mathrm{x}^2 \\ & 2 \mathrm{x}^2+\mathrm{x}-10=0 \\ & \mathrm{x}=2\end{aligned}$

Asked in: JEE Main 2024 (08 Apr Shift 2)

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